You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)Output: 7 -> 0 -> 8Explanation: 342 + 465 = 807.
核心: 根据 sum 的值来决定是否要处理进位
// Keyword: single linked list/*** Definition for singly-linked list.* function ListNode(val) {* this.val = val;* this.next = null;* }*//*** @param {ListNode} l1* @param {ListNode} l2* @return {ListNode}*/var addTwoNumbers = function(l1, l2) {let flag = 0let head = null,temp = nullwhile (l1 || l2) {let sum = flagif (l1) {sum += l1.vall1 = l1.next}if (l2) {sum += l2.vall2 = l2.next}const list = new ListNode(sum % 10)if (head === null) {head = listtemp = list} else {temp.next = listtemp = list}// 处理进位flag = 0if (sum >= 10) {flag = 1}}if (flag === 1) {const result = new ListNode(1)temp.next = resulttemp = result}return head}
445