Given an array nums of distinct integers, return all the possible permutations. You can return the answer in any order.
Example 1:
Input: nums = [1,2,3]Output: [[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]
Example 2:
Input: nums = [0,1]Output: [[0,1],[1,0]]
Example 3:
Input: nums = [1]Output: [[1]]
Constraints:
All the integers of nums are unique
该问题可以看成为一道排列问题, 排列问题的一种常见解法是回溯法:
* 1* 2* 3* 3* 2* 2* 1* 3* 3* 1* 3* 1* 2* 2* 1
/*** @param {number[]} nums* @return {number[][]}*/var permute = function (nums) {const res = []backtracking(nums, [], res)return res};var backtracking = function(nums, temp, res) {if (temp.length === nums.length) {res.push([...temp])return}for (let i = 0; i < nums.length; i++) {if (!temp.includes(nums[i])) {temp.push(nums[i])backtracking(nums, temp, res)temp.pop(nums[i])} else {continue}}}